Solve (41/3-3)*(6/7-1/4)

$$( 4 \frac { 1 } { 3 } -3) \times ( \frac{ 6 }{ 7 } - \frac{ 1 }{ 4 } )$$

Evaluate

$$\frac{17}{21}\approx 0.80952381$$

Solution Steps

Multiply 4 and 3 to get 12.

$$\left(\frac{12+1}{3}-3\right)\left(\frac{6}{7}-\frac{1}{4}\right)$$

Add 12 and 1 to get 13.

$$\left(\frac{13}{3}-3\right)\left(\frac{6}{7}-\frac{1}{4}\right)$$

Convert 3 to fraction \frac{9}{3}.

$$\left(\frac{13}{3}-\frac{9}{3}\right)\left(\frac{6}{7}-\frac{1}{4}\right)$$

Since \frac{13}{3} and \frac{9}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{13-9}{3}\left(\frac{6}{7}-\frac{1}{4}\right)$$

Subtract 9 from 13 to get 4.

$$\frac{4}{3}\left(\frac{6}{7}-\frac{1}{4}\right)$$

Least common multiple of 7 and 4 is 28. Convert \frac{6}{7} and \frac{1}{4} to fractions with denominator 28.

$$\frac{4}{3}\left(\frac{24}{28}-\frac{7}{28}\right)$$

Since \frac{24}{28} and \frac{7}{28} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4}{3}\times \frac{24-7}{28}$$

Subtract 7 from 24 to get 17.

$$\frac{4}{3}\times \frac{17}{28}$$

Multiply \frac{4}{3} times \frac{17}{28} by multiplying numerator times numerator and denominator times denominator.

$$\frac{4\times 17}{3\times 28}$$

Do the multiplications in the fraction \frac{4\times 17}{3\times 28}.

$$\frac{68}{84}$$

Reduce the fraction \frac{68}{84} to lowest terms by extracting and canceling out 4.

$$\frac{17}{21}$$

Factor

$$\frac{17}{3 \cdot 7} = 0.8095238095238095$$