Solve (346/6+4*5)-(16*3-5*8)+(18-2+5*3)-(7*6-5)

$$( 346 / 6 + 4 \times 5 ) - ( 16 \times 3 - 5 \times 8 ) + ( 18 - 2 + 5 \times 3 ) - ( 7 \times 6 - 5 )$$

Evaluate

$$\frac{191}{3}\approx 63.666666667$$

Solution Steps

Reduce the fraction \frac{346}{6} to lowest terms by extracting and canceling out 2.

$$\frac{173}{3}+4\times 5-\left(16\times 3-5\times 8\right)+18-2+5\times 3-\left(7\times 6-5\right)$$

Multiply 4 and 5 to get 20.

$$\frac{173}{3}+20-\left(16\times 3-5\times 8\right)+18-2+5\times 3-\left(7\times 6-5\right)$$

Convert 20 to fraction \frac{60}{3}.

$$\frac{173}{3}+\frac{60}{3}-\left(16\times 3-5\times 8\right)+18-2+5\times 3-\left(7\times 6-5\right)$$

Since \frac{173}{3} and \frac{60}{3} have the same denominator, add them by adding their numerators.

$$\frac{173+60}{3}-\left(16\times 3-5\times 8\right)+18-2+5\times 3-\left(7\times 6-5\right)$$

Add 173 and 60 to get 233.

$$\frac{233}{3}-\left(16\times 3-5\times 8\right)+18-2+5\times 3-\left(7\times 6-5\right)$$

Multiply 16 and 3 to get 48.

$$\frac{233}{3}-\left(48-5\times 8\right)+18-2+5\times 3-\left(7\times 6-5\right)$$

Multiply 5 and 8 to get 40.

$$\frac{233}{3}-\left(48-40\right)+18-2+5\times 3-\left(7\times 6-5\right)$$

Subtract 40 from 48 to get 8.

$$\frac{233}{3}-8+18-2+5\times 3-\left(7\times 6-5\right)$$

Convert 8 to fraction \frac{24}{3}.

$$\frac{233}{3}-\frac{24}{3}+18-2+5\times 3-\left(7\times 6-5\right)$$

Since \frac{233}{3} and \frac{24}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{233-24}{3}+18-2+5\times 3-\left(7\times 6-5\right)$$

Subtract 24 from 233 to get 209.

$$\frac{209}{3}+18-2+5\times 3-\left(7\times 6-5\right)$$

Convert 18 to fraction \frac{54}{3}.

$$\frac{209}{3}+\frac{54}{3}-2+5\times 3-\left(7\times 6-5\right)$$

Since \frac{209}{3} and \frac{54}{3} have the same denominator, add them by adding their numerators.

$$\frac{209+54}{3}-2+5\times 3-\left(7\times 6-5\right)$$

Add 209 and 54 to get 263.

$$\frac{263}{3}-2+5\times 3-\left(7\times 6-5\right)$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{263}{3}-\frac{6}{3}+5\times 3-\left(7\times 6-5\right)$$

Since \frac{263}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{263-6}{3}+5\times 3-\left(7\times 6-5\right)$$

Subtract 6 from 263 to get 257.

$$\frac{257}{3}+5\times 3-\left(7\times 6-5\right)$$

Multiply 5 and 3 to get 15.

$$\frac{257}{3}+15-\left(7\times 6-5\right)$$

Convert 15 to fraction \frac{45}{3}.

$$\frac{257}{3}+\frac{45}{3}-\left(7\times 6-5\right)$$

Since \frac{257}{3} and \frac{45}{3} have the same denominator, add them by adding their numerators.

$$\frac{257+45}{3}-\left(7\times 6-5\right)$$

Add 257 and 45 to get 302.

$$\frac{302}{3}-\left(7\times 6-5\right)$$

Multiply 7 and 6 to get 42.

$$\frac{302}{3}-\left(42-5\right)$$

Subtract 5 from 42 to get 37.

$$\frac{302}{3}-37$$

Convert 37 to fraction \frac{111}{3}.

$$\frac{302}{3}-\frac{111}{3}$$

Since \frac{302}{3} and \frac{111}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{302-111}{3}$$

Subtract 111 from 302 to get 191.

$$\frac{191}{3}$$

Factor

$$\frac{191}{3} = 63\frac{2}{3} = 63.666666666666664$$