Solve (30-5*7+250:50):6-(5*5-35)

$$( 30 - 5 \cdot 7 + 250 : 50 ) : 6 - ( 5 \cdot 5 - 35 )$$

Evaluate

$$10$$

Solution Steps

Multiply 5 and 7 to get 35.

$$\frac{30-35+\frac{250}{50}}{6}-\left(5\times 5-35\right)$$

Subtract 35 from 30 to get -5.

$$\frac{-5+\frac{250}{50}}{6}-\left(5\times 5-35\right)$$

Divide 250 by 50 to get 5.

$$\frac{-5+5}{6}-\left(5\times 5-35\right)$$

Add -5 and 5 to get 0.

$$\frac{0}{6}-\left(5\times 5-35\right)$$

Zero divided by any non-zero number gives zero.

$$0-\left(5\times 5-35\right)$$

Multiply 5 and 5 to get 25.

$$0-\left(25-35\right)$$

Subtract 35 from 25 to get -10.

$$0-\left(-10\right)$$

The opposite of -10 is 10.

$$0+10$$

Add 0 and 10 to get 10.

$$10$$

Factor

$$2\times 5$$