Solve (30+5)div[5*(4-3)]*[(6*8)div(6div3)]

$$( 30 + 5 ) \div [ 5 \times ( 4 - 3 ) ] \times [ ( 6 \times 8 ) \div ( 6 \div 3 ) ]$$

Evaluate

$$168$$

Solution Steps

Add 30 and 5 to get 35.

$$\frac{35}{5\left(4-3\right)}\times \frac{6\times 8}{\frac{6}{3}}$$

Subtract 3 from 4 to get 1.

$$\frac{35}{5\times 1}\times \frac{6\times 8}{\frac{6}{3}}$$

Multiply 5 and 1 to get 5.

$$\frac{35}{5}\times \frac{6\times 8}{\frac{6}{3}}$$

Divide 35 by 5 to get 7.

$$7\times \frac{6\times 8}{\frac{6}{3}}$$

Multiply 6 and 8 to get 48.

$$7\times \frac{48}{\frac{6}{3}}$$

Divide 6 by 3 to get 2.

$$7\times \frac{48}{2}$$

Divide 48 by 2 to get 24.

$$7\times 24$$

Multiply 7 and 24 to get 168.

$$168$$

Factor

$$2^{3}\times 3\times 7$$