Solve (3x-8)+(7-4x)+(2x-1)

$$( 3 x - 8 ) + ( 7 - 4 x ) + ( 2 x - 1 )$$

Evaluate

$$x-2$$

Solution Steps

Add -8 and 7 to get -1.

$$3x-1-4x+2x-1$$

Combine 3x and -4x to get -x.

$$-x-1+2x-1$$

Combine -x and 2x to get x.

$$x-1-1$$

Subtract 1 from -1 to get -2.

$$x-2$$

Differentiate w.r.t. x

$$1$$

Steps Using Derivative Rule for Sum

Add -8 and 7 to get -1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x-1-4x+2x-1)$$

Combine 3x and -4x to get -x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-x-1+2x-1)$$

Combine -x and 2x to get x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x-1-1)$$

Subtract 1 from -1 to get -2.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x-2)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$x^{1-1}$$

Subtract 1 from 1.

$$x^{0}$$

For any term t except 0, t^{0}=1.

$$1$$