Solve (3x-5)^2=9x^2

$$( 3 x - 5 ) ^ { 2 } = 9 x ^ { 2 }$$

Solve for x

$$x=\frac{5}{6}\approx 0.833333333$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(3x-5\right)^{2}.

$$9x^{2}-30x+25=9x^{2}$$

Subtract 9x^{2} from both sides.

$$9x^{2}-30x+25-9x^{2}=0$$

Combine 9x^{2} and -9x^{2} to get 0.

$$-30x+25=0$$

Subtract 25 from both sides. Anything subtracted from zero gives its negation.

$$-30x=-25$$

Divide both sides by -30.

$$x=\frac{-25}{-30}$$

Reduce the fraction \frac{-25}{-30} to lowest terms by extracting and canceling out -5.

$$x=\frac{5}{6}$$