Solve (3x-4)*(x-1)*(6+x)

$$( 3 x - 4 ) \cdot ( x - 1 ) \cdot ( 6 + x )$$

Evaluate

$$\left(x-1\right)\left(3x-4\right)\left(x+6\right)$$

Solution Steps

Apply the distributive property by multiplying each term of 3x-4 by each term of x-1.

$$\left(3x^{2}-3x-4x+4\right)\left(6+x\right)$$

Combine -3x and -4x to get -7x.

$$\left(3x^{2}-7x+4\right)\left(6+x\right)$$

Apply the distributive property by multiplying each term of 3x^{2}-7x+4 by each term of 6+x.

$$18x^{2}+3x^{3}-42x-7x^{2}+24+4x$$

Combine 18x^{2} and -7x^{2} to get 11x^{2}.

$$11x^{2}+3x^{3}-42x+24+4x$$

Combine -42x and 4x to get -38x.

$$11x^{2}+3x^{3}-38x+24$$

Expand

$$3x^{3}+11x^{2}-38x+24$$

Solution Steps

Apply the distributive property by multiplying each term of 3x-4 by each term of x-1.

$$\left(3x^{2}-3x-4x+4\right)\left(6+x\right)$$

Combine -3x and -4x to get -7x.

$$\left(3x^{2}-7x+4\right)\left(6+x\right)$$

Apply the distributive property by multiplying each term of 3x^{2}-7x+4 by each term of 6+x.

$$18x^{2}+3x^{3}-42x-7x^{2}+24+4x$$

Combine 18x^{2} and -7x^{2} to get 11x^{2}.

$$11x^{2}+3x^{3}-42x+24+4x$$

Combine -42x and 4x to get -38x.

$$11x^{2}+3x^{3}-38x+24$$