Solve (3x-2)(6x+5)-3(3x-1)(2x+1

$$( 3 x - 2 ) ( 6 x + 5 ) - 3 ( 3 x - 1 ) ( 2 x + 1$$

Evaluate

$$-7$$

Solution Steps

Apply the distributive property by multiplying each term of 3x-2 by each term of 6x+5.

$$18x^{2}+15x-12x-10-3\left(3x-1\right)\left(2x+1\right)$$

Combine 15x and -12x to get 3x.

$$18x^{2}+3x-10-3\left(3x-1\right)\left(2x+1\right)$$

Use the distributive property to multiply -3 by 3x-1.

$$18x^{2}+3x-10+\left(-9x+3\right)\left(2x+1\right)$$

Apply the distributive property by multiplying each term of -9x+3 by each term of 2x+1.

$$18x^{2}+3x-10-18x^{2}-9x+6x+3$$

Combine -9x and 6x to get -3x.

$$18x^{2}+3x-10-18x^{2}-3x+3$$

Combine 18x^{2} and -18x^{2} to get 0.

$$3x-10-3x+3$$

Combine 3x and -3x to get 0.

$$-10+3$$

Add -10 and 3 to get -7.

$$-7$$

Factor

$$-7$$