Solve (3x)^2-(3x+2)(2x-1)-3(x-3)(x+3)=0

$$( 3 x ) ^ { 2 } - ( 3 x + 2 ) ( 2 x - 1 ) - 3 ( x - 3 ) ( x + 3 ) = 0$$

Solve for x

$$x=29$$

Steps for Solving Linear Equation

Expand \left(3x\right)^{2}.

$$3^{2}x^{2}-\left(3x+2\right)\left(2x-1\right)-3\left(x-3\right)\left(x+3\right)=0$$

Calculate 3 to the power of 2 and get 9.

$$9x^{2}-\left(3x+2\right)\left(2x-1\right)-3\left(x-3\right)\left(x+3\right)=0$$

Use the distributive property to multiply 3x+2 by 2x-1 and combine like terms.

$$9x^{2}-\left(6x^{2}+x-2\right)-3\left(x-3\right)\left(x+3\right)=0$$

To find the opposite of 6x^{2}+x-2, find the opposite of each term.

$$9x^{2}-6x^{2}-x+2-3\left(x-3\right)\left(x+3\right)=0$$

Combine 9x^{2} and -6x^{2} to get 3x^{2}.

$$3x^{2}-x+2-3\left(x-3\right)\left(x+3\right)=0$$

Use the distributive property to multiply -3 by x-3.

$$3x^{2}-x+2+\left(-3x+9\right)\left(x+3\right)=0$$

Use the distributive property to multiply -3x+9 by x+3 and combine like terms.

$$3x^{2}-x+2-3x^{2}+27=0$$

Combine 3x^{2} and -3x^{2} to get 0.

$$-x+2+27=0$$

Add 2 and 27 to get 29.

$$-x+29=0$$

Subtract 29 from both sides. Anything subtracted from zero gives its negation.

$$-x=-29$$

Multiply both sides by -1.

$$x=29$$