Solve (3x^3+4x^2)+(3x^3-4x^2-9x)=

$$( 3 x ^ { 3 } + 4 x ^ { 2 } ) + ( 3 x ^ { 3 } - 4 x ^ { 2 } - 9 x ) =$$

Evaluate

$$6x^{3}-9x$$

Solution Steps

Combine 3x^{3} and 3x^{3} to get 6x^{3}.

$$6x^{3}+4x^{2}-4x^{2}-9x$$

Combine 4x^{2} and -4x^{2} to get 0.

$$6x^{3}-9x$$

Factor

$$3x\left(2x^{2}-3\right)$$

Solution Steps

Factor out x.

$$x\left(3x^{2}+4x+3x^{2}-4x-9\right)$$

Consider 3x^{2}+4x+3x^{2}-4x-9. Multiply and combine like terms.

$$6x^{2}-9$$

Consider 6x^{2}-9. Factor out 3.

$$3\left(2x^{2}-3\right)$$

Rewrite the complete factored expression. Polynomial 2x^{2}-3 is not factored since it does not have any rational roots.

$$3x\left(2x^{2}-3\right)$$