Solve (3x^2)^2*(-4y^2)div(6xy^2)

$$( 3 x ^ { 2 } ) ^ { 2 } \cdot ( - 4 y ^ { 2 } ) \div ( 6 x y ^ { 2 } )$$

Evaluate

$$-6x^{3}$$

Solution Steps

Cancel out 2y^{2} in both numerator and denominator.

$$\frac{-2\times \left(3x^{2}\right)^{2}}{3x}$$

Expand \left(3x^{2}\right)^{2}.

$$\frac{-2\times 3^{2}\left(x^{2}\right)^{2}}{3x}$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$\frac{-2\times 3^{2}x^{4}}{3x}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{-2\times 9x^{4}}{3x}$$

Multiply -2 and 9 to get -18.

$$\frac{-18x^{4}}{3x}$$

Cancel out 3x in both numerator and denominator.

$$-6x^{3}$$

Expand

$$-6x^{3}$$

Solution Steps

Cancel out 2y^{2} in both numerator and denominator.

$$\frac{-2\times \left(3x^{2}\right)^{2}}{3x}$$

Expand \left(3x^{2}\right)^{2}.

$$\frac{-2\times 3^{2}\left(x^{2}\right)^{2}}{3x}$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$\frac{-2\times 3^{2}x^{4}}{3x}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{-2\times 9x^{4}}{3x}$$

Multiply -2 and 9 to get -18.

$$\frac{-18x^{4}}{3x}$$

Cancel out 3x in both numerator and denominator.

$$-6x^{3}$$