Solve (3x+5)(-7/5x+44)-80

$$( 3 x + 5 ) ( - \frac { 7 } { 5 } x + 44 ) - 80$$

Evaluate

$$-\frac{21x^{2}}{5}+125x+140$$

Solution Steps

Apply the distributive property by multiplying each term of 3x+5 by each term of -\frac{7}{5}x+44.

$$3x\left(-\frac{7}{5}\right)x+132x+5\left(-\frac{7}{5}\right)x+220-80$$

Multiply x and x to get x^{2}.

$$3x^{2}\left(-\frac{7}{5}\right)+132x+5\left(-\frac{7}{5}\right)x+220-80$$

Express 3\left(-\frac{7}{5}\right) as a single fraction.

$$\frac{3\left(-7\right)}{5}x^{2}+132x+5\left(-\frac{7}{5}\right)x+220-80$$

Multiply 3 and -7 to get -21.

$$\frac{-21}{5}x^{2}+132x+5\left(-\frac{7}{5}\right)x+220-80$$

Fraction \frac{-21}{5} can be rewritten as -\frac{21}{5} by extracting the negative sign.

$$-\frac{21}{5}x^{2}+132x+5\left(-\frac{7}{5}\right)x+220-80$$

Cancel out 5 and 5.

$$-\frac{21}{5}x^{2}+132x-7x+220-80$$

Combine 132x and -7x to get 125x.

$$-\frac{21}{5}x^{2}+125x+220-80$$

Subtract 80 from 220 to get 140.

$$-\frac{21}{5}x^{2}+125x+140$$

Expand

$$-\frac{21x^{2}}{5}+125x+140$$

Solution Steps

Apply the distributive property by multiplying each term of 3x+5 by each term of -\frac{7}{5}x+44.

$$3x\left(-\frac{7}{5}\right)x+132x+5\left(-\frac{7}{5}\right)x+220-80$$

Multiply x and x to get x^{2}.

$$3x^{2}\left(-\frac{7}{5}\right)+132x+5\left(-\frac{7}{5}\right)x+220-80$$

Express 3\left(-\frac{7}{5}\right) as a single fraction.

$$\frac{3\left(-7\right)}{5}x^{2}+132x+5\left(-\frac{7}{5}\right)x+220-80$$

Multiply 3 and -7 to get -21.

$$\frac{-21}{5}x^{2}+132x+5\left(-\frac{7}{5}\right)x+220-80$$

Fraction \frac{-21}{5} can be rewritten as -\frac{21}{5} by extracting the negative sign.

$$-\frac{21}{5}x^{2}+132x+5\left(-\frac{7}{5}\right)x+220-80$$

Cancel out 5 and 5.

$$-\frac{21}{5}x^{2}+132x-7x+220-80$$

Combine 132x and -7x to get 125x.

$$-\frac{21}{5}x^{2}+125x+220-80$$

Subtract 80 from 220 to get 140.

$$-\frac{21}{5}x^{2}+125x+140$$