Solve (3x+4)^2=14

$$( 3 x + 4 ) ^ { 2 } = 14$$

Solve for x

$$x=\frac{\sqrt{14}-4}{3}\approx -0.086114204$$

$$x=\frac{-\sqrt{14}-4}{3}\approx -2.580552462$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$3x+4=\sqrt{14} 3x+4=-\sqrt{14}$$

Subtract 4 from both sides of the equation.

$$3x+4-4=\sqrt{14}-4 3x+4-4=-\sqrt{14}-4$$

Subtracting 4 from itself leaves 0.

$$3x=\sqrt{14}-4 3x=-\sqrt{14}-4$$

Subtract 4 from \sqrt{14}.

$$3x=\sqrt{14}-4$$

Subtract 4 from -\sqrt{14}.

$$3x=-\sqrt{14}-4$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{\sqrt{14}-4}{3} \frac{3x}{3}=\frac{-\sqrt{14}-4}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{\sqrt{14}-4}{3} x=\frac{-\sqrt{14}-4}{3}$$