Solve for x
x\in \left(-2,-1\right)
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-x-2<0 3x+3<0
For the product to be positive, -x-2 and 3x+3 have to be both negative or both positive. Consider the case when -x-2 and 3x+3 are both negative.
x\in \left(-2,-1\right)
The solution satisfying both inequalities is x\in \left(-2,-1\right).
3x+3>0 -x-2>0
Consider the case when -x-2 and 3x+3 are both positive.
x\in \emptyset
This is false for any x.
x\in \left(-2,-1\right)
The final solution is the union of the obtained solutions.
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