Solve (3x+2)^2=6

$$( 3 x + 2 ) ^ { 2 } = 6$$

Solve for x

$$x=\frac{\sqrt{6}-2}{3}\approx 0.149829914$$

$$x=\frac{-\sqrt{6}-2}{3}\approx -1.483163248$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$3x+2=\sqrt{6} 3x+2=-\sqrt{6}$$

Subtract 2 from both sides of the equation.

$$3x+2-2=\sqrt{6}-2 3x+2-2=-\sqrt{6}-2$$

Subtracting 2 from itself leaves 0.

$$3x=\sqrt{6}-2 3x=-\sqrt{6}-2$$

Subtract 2 from \sqrt{6}.

$$3x=\sqrt{6}-2$$

Subtract 2 from -\sqrt{6}.

$$3x=-\sqrt{6}-2$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{\sqrt{6}-2}{3} \frac{3x}{3}=\frac{-\sqrt{6}-2}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{\sqrt{6}-2}{3} x=\frac{-\sqrt{6}-2}{3}$$