Solve for x
x=\frac{\sqrt{10}-2}{3}\approx 0.387425887
x=\frac{-\sqrt{10}-2}{3}\approx -1.72075922
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3x+2=\sqrt{10} 3x+2=-\sqrt{10}
Take the square root of both sides of the equation.
3x+2-2=\sqrt{10}-2 3x+2-2=-\sqrt{10}-2
Subtract 2 from both sides of the equation.
3x=\sqrt{10}-2 3x=-\sqrt{10}-2
Subtracting 2 from itself leaves 0.
3x=\sqrt{10}-2
Subtract 2 from \sqrt{10}.
3x=-\sqrt{10}-2
Subtract 2 from -\sqrt{10}.
\frac{3x}{3}=\frac{\sqrt{10}-2}{3} \frac{3x}{3}=\frac{-\sqrt{10}-2}{3}
Divide both sides by 3.
x=\frac{\sqrt{10}-2}{3} x=\frac{-\sqrt{10}-2}{3}
Dividing by 3 undoes the multiplication by 3.
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