Solve (3x+1)^2-2x=9x^2+5

$$( 3 x + 1 ) ^ { 2 } - 2 x = 9 x ^ { 2 } + 5$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(3x+1\right)^{2}.

$$9x^{2}+6x+1-2x=9x^{2}+5$$

Combine 6x and -2x to get 4x.

$$9x^{2}+4x+1=9x^{2}+5$$

Subtract 9x^{2} from both sides.

$$9x^{2}+4x+1-9x^{2}=5$$

Combine 9x^{2} and -9x^{2} to get 0.

$$4x+1=5$$

Subtract 1 from both sides.

$$4x=5-1$$

Subtract 1 from 5 to get 4.

$$4x=4$$

Divide both sides by 4.

$$x=\frac{4}{4}$$

Divide 4 by 4 to get 1.

$$x=1$$