Solve (3x+13/31):8=11/8

$$( 3 x + \frac { 13 } { 31 } ) : 8 = 1 \frac { 1 } { 8 }$$

Solve for x

$$x = \frac{266}{93} = 2\frac{80}{93} \approx 2.860215054$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 8.

$$3x+\frac{13}{31}=1\times 8+1$$

Multiply 1 and 8 to get 8.

$$3x+\frac{13}{31}=8+1$$

Add 8 and 1 to get 9.

$$3x+\frac{13}{31}=9$$

Subtract \frac{13}{31} from both sides.

$$3x=9-\frac{13}{31}$$

Convert 9 to fraction \frac{279}{31}.

$$3x=\frac{279}{31}-\frac{13}{31}$$

Since \frac{279}{31} and \frac{13}{31} have the same denominator, subtract them by subtracting their numerators.

$$3x=\frac{279-13}{31}$$

Subtract 13 from 279 to get 266.

$$3x=\frac{266}{31}$$

Divide both sides by 3.

$$x=\frac{\frac{266}{31}}{3}$$

Express \frac{\frac{266}{31}}{3} as a single fraction.

$$x=\frac{266}{31\times 3}$$

Multiply 31 and 3 to get 93.

$$x=\frac{266}{93}$$