Solve (3t+6)+(3t+7)

$$( 3 t + 6 ) + ( 3 t + 7 )$$

Evaluate

$$6t+13$$

Solution Steps

Combine 3t and 3t to get 6t.

$$6t+6+7$$

Add 6 and 7 to get 13.

$$6t+13$$

Differentiate w.r.t. t

$$6$$

Steps Using Derivative Rule for Sum

Combine 3t and 3t to get 6t.

$$\frac{\mathrm{d}}{\mathrm{d}t}(6t+6+7)$$

Add 6 and 7 to get 13.

$$\frac{\mathrm{d}}{\mathrm{d}t}(6t+13)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$6t^{1-1}$$

Subtract 1 from 1.

$$6t^{0}$$

For any term t except 0, t^{0}=1.

$$6\times 1$$

For any term t, t\times 1=t and 1t=t.

$$6$$