Solve (3p^2+4p^2-5)-(2p^3+p^2+7q)

$$( 3 p ^ { 2 } + 4 p ^ { 2 } - 5 ) - ( 2 p ^ { 3 } + p ^ { 2 } + 7 q )$$

Evaluate

$$-2p^{3}+6p^{2}-7q-5$$

Solution Steps

Combine 3p^{2} and 4p^{2} to get 7p^{2}.

$$7p^{2}-5-\left(2p^{3}+p^{2}+7q\right)$$

To find the opposite of 2p^{3}+p^{2}+7q, find the opposite of each term.

$$7p^{2}-5-2p^{3}-p^{2}-7q$$

Combine 7p^{2} and -p^{2} to get 6p^{2}.

$$6p^{2}-5-2p^{3}-7q$$

Expand

$$-2p^{3}+6p^{2}-7q-5$$

Solution Steps

Combine 3p^{2} and 4p^{2} to get 7p^{2}.

$$7p^{2}-5-\left(2p^{3}+p^{2}+7q\right)$$

To find the opposite of 2p^{3}+p^{2}+7q, find the opposite of each term.

$$7p^{2}-5-2p^{3}-p^{2}-7q$$

Combine 7p^{2} and -p^{2} to get 6p^{2}.

$$6p^{2}-5-2p^{3}-7q$$