Solve (3i+2)(2i+3)

$$( 3 i + 2 ) ( 2 i + 3 )$$

Evaluate

$$13i$$

Solution Steps

Apply the distributive property by multiplying each term of 3i+2 by each term of 2i+3.

$$-6+9i+4i+6$$

Combine the real and imaginary parts.

$$-6+6+\left(9+4\right)i$$

Do the additions.

$$13i$$

Real Part

$$0$$

Solution Steps

Apply the distributive property by multiplying each term of 3i+2 by each term of 2i+3.

$$Re(-6+9i+4i+6)$$

Combine the real and imaginary parts in -6+9i+4i+6.

$$Re(-6+6+\left(9+4\right)i)$$

Do the additions in -6+6+\left(9+4\right)i.

$$Re(13i)$$

The real part of 13i is 0.

$$0$$