Solve (3b^0-5^1-20^6i^11)*3

$$( 3 b ^ { 0 } - 5 ^ { 1 } - 20 ^ { 6 } i ^ { 11 } ) \times 3$$

Evaluate

$$-6+192000000i$$

Solution Steps

Calculate b to the power of 0 and get 1.

$$\left(3\times 1-5^{1}-20^{6}i^{11}\right)\times 3$$

Multiply 3 and 1 to get 3.

$$\left(3-5^{1}-20^{6}i^{11}\right)\times 3$$

Calculate 5 to the power of 1 and get 5.

$$\left(3-5-20^{6}i^{11}\right)\times 3$$

Subtract 5 from 3 to get -2.

$$\left(-2-20^{6}i^{11}\right)\times 3$$

Calculate 20 to the power of 6 and get 64000000.

$$\left(-2-64000000i^{11}\right)\times 3$$

Calculate i to the power of 11 and get -i.

$$\left(-2-64000000\left(-i\right)\right)\times 3$$

Multiply 64000000 and -i to get -64000000i.

$$\left(-2-\left(-64000000i\right)\right)\times 3$$

The opposite of -64000000i is 64000000i.

$$\left(-2+64000000i\right)\times 3$$

Multiply -2+64000000i and 3 to get -6+192000000i.

$$-6+192000000i$$