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Solve for b
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Solve for a
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3a-2b-2b<3a
Subtract 2b from both sides.
3a-4b<3a
Combine -2b and -2b to get -4b.
-4b<3a-3a
Subtract 3a from both sides.
-4b<0
Combine 3a and -3a to get 0.
b>0
Product of two numbers is <0 if one is >0 and the other is <0. Since -4<0, b must be >0.