Solve (3a^{4})^0+4a^0-(2a^0)^2

$$( 3 a ^ { 4 } ) ^ { 0 } + 4 a ^ { 0 } - ( 2 a ^ { 0 } ) ^ { 2 }$$

Evaluate

$$1$$

Solution Steps

Calculate 3a^{4} to the power of 0 and get 1.

$$1+4a^{0}-\left(2a^{0}\right)^{2}$$

Calculate a to the power of 0 and get 1.

$$1+4\times 1-\left(2a^{0}\right)^{2}$$

Multiply 4 and 1 to get 4.

$$1+4-\left(2a^{0}\right)^{2}$$

Add 1 and 4 to get 5.

$$5-\left(2a^{0}\right)^{2}$$

Calculate a to the power of 0 and get 1.

$$5-\left(2\times 1\right)^{2}$$

Multiply 2 and 1 to get 2.

$$5-2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$5-4$$

Subtract 4 from 5 to get 1.

$$1$$

Factor

$$1$$