Solve (3-x)^2+25=0

$$( 3 - x ) ^ { 2 } + 25 = 0$$

Solve for x (complex solution)

$$x=3+5i$$

$$x=3-5i$$

Steps by Finding Square Root

Subtracting 25 from itself leaves 0.

$$\left(-x+3\right)^{2}=-25$$

Take the square root of both sides of the equation.

$$-x+3=5i -x+3=-5i$$

Subtract 3 from both sides of the equation.

$$-x+3-3=5i-3 -x+3-3=-5i-3$$

Subtracting 3 from itself leaves 0.

$$-x=5i-3 -x=-5i-3$$

Subtract 3 from 5i.

$$-x=-3+5i$$

Subtract 3 from -5i.

$$-x=-3-5i$$

Divide both sides by -1.

$$\frac{-x}{-1}=\frac{-3+5i}{-1} \frac{-x}{-1}=\frac{-3-5i}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=\frac{-3+5i}{-1} x=\frac{-3-5i}{-1}$$

Divide -3+5i by -1.

$$x=3-5i$$

Divide -3-5i by -1.

$$x=3+5i$$

The equation is now solved.

$$x=3-5i x=3+5i$$