Solve (3-2x)+(4x-4)

$$( 3 - 2 x ) + ( 4 x - 4 )$$

Evaluate

$$2x-1$$

Solution Steps

Combine -2x and 4x to get 2x.

$$3+2x-4$$

Subtract 4 from 3 to get -1.

$$-1+2x$$

Differentiate w.r.t. x

$$2$$

Steps Using Derivative Rule for Sum

Combine -2x and 4x to get 2x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3+2x-4)$$

Subtract 4 from 3 to get -1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-1+2x)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2x^{1-1}$$

Subtract 1 from 1.

$$2x^{0}$$

For any term t except 0, t^{0}=1.

$$2\times 1$$

For any term t, t\times 1=t and 1t=t.

$$2$$