Solve (3-1/3)*(3+1/3)

$$( 3 - \frac { 1 } { 3 } ) \cdot ( 3 + \frac { 1 } { 3 } )$$

Evaluate

$$\frac{80}{9}\approx 8.888888889$$

Solution Steps

Convert 3 to fraction \frac{9}{3}.

$$\left(\frac{9}{3}-\frac{1}{3}\right)\left(3+\frac{1}{3}\right)$$

Since \frac{9}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-1}{3}\left(3+\frac{1}{3}\right)$$

Subtract 1 from 9 to get 8.

$$\frac{8}{3}\left(3+\frac{1}{3}\right)$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{8}{3}\left(\frac{9}{3}+\frac{1}{3}\right)$$

Since \frac{9}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{8}{3}\times \frac{9+1}{3}$$

Add 9 and 1 to get 10.

$$\frac{8}{3}\times \frac{10}{3}$$

Multiply \frac{8}{3} times \frac{10}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{8\times 10}{3\times 3}$$

Do the multiplications in the fraction \frac{8\times 10}{3\times 3}.

$$\frac{80}{9}$$

Factor

$$\frac{2 ^ {4} \cdot 5}{3 ^ {2}} = 8\frac{8}{9} = 8.88888888888889$$