Solve (3)8*1-6-11+261/2*1/13

$$( 3 ) 8 \times 1 - 6 - 11 + 26 \frac { 1 } { 2 } \times \frac { 1 } { 13 }$$

Evaluate

$$\frac{235}{26}\approx 9.038461538$$

Solution Steps

Multiply 3 and 8 to get 24.

$$24\times 1-6-11+\frac{26\times 2+1}{2}\times \frac{1}{13}$$

Multiply 24 and 1 to get 24.

$$24-6-11+\frac{26\times 2+1}{2}\times \frac{1}{13}$$

Subtract 6 from 24 to get 18.

$$18-11+\frac{26\times 2+1}{2}\times \frac{1}{13}$$

Subtract 11 from 18 to get 7.

$$7+\frac{26\times 2+1}{2}\times \frac{1}{13}$$

Multiply 26 and 2 to get 52.

$$7+\frac{52+1}{2}\times \frac{1}{13}$$

Add 52 and 1 to get 53.

$$7+\frac{53}{2}\times \frac{1}{13}$$

Multiply \frac{53}{2} times \frac{1}{13} by multiplying numerator times numerator and denominator times denominator.

$$7+\frac{53\times 1}{2\times 13}$$

Do the multiplications in the fraction \frac{53\times 1}{2\times 13}.

$$7+\frac{53}{26}$$

Convert 7 to fraction \frac{182}{26}.

$$\frac{182}{26}+\frac{53}{26}$$

Since \frac{182}{26} and \frac{53}{26} have the same denominator, add them by adding their numerators.

$$\frac{182+53}{26}$$

Add 182 and 53 to get 235.

$$\frac{235}{26}$$

Factor

$$\frac{5 \cdot 47}{2 \cdot 13} = 9\frac{1}{26} = 9.038461538461538$$