Solve (3)-1/4*(+3)div(-1/2)^3,quad(4)-3^2*(-8)div3div(-2)

$$( 3 ) - \frac { 1 } { 4 } \times ( + 3 ) \div ( - \frac { 1 } { 2 } ) ^ { 3 } , \quad ( 4 ) - 3 ^ { 2 } \times ( - 8 ) \div 3 \div ( - 2 )$$

Sort

$$-8,9$$

Solution Steps

Multiply \frac{1}{4} and 3 to get \frac{3}{4}.

$$sort(3-\frac{\frac{3}{4}}{\left(-\frac{1}{2}\right)^{3}},4-\frac{\frac{3^{2}\left(-8\right)}{3}}{-2})$$

Calculate -\frac{1}{2} to the power of 3 and get -\frac{1}{8}.

$$sort(3-\frac{\frac{3}{4}}{-\frac{1}{8}},4-\frac{\frac{3^{2}\left(-8\right)}{3}}{-2})$$

Divide \frac{3}{4} by -\frac{1}{8} by multiplying \frac{3}{4} by the reciprocal of -\frac{1}{8}.

$$sort(3-\frac{3}{4}\left(-8\right),4-\frac{\frac{3^{2}\left(-8\right)}{3}}{-2})$$

Express \frac{3}{4}\left(-8\right) as a single fraction.

$$sort(3-\frac{3\left(-8\right)}{4},4-\frac{\frac{3^{2}\left(-8\right)}{3}}{-2})$$

Multiply 3 and -8 to get -24.

$$sort(3-\frac{-24}{4},4-\frac{\frac{3^{2}\left(-8\right)}{3}}{-2})$$

Divide -24 by 4 to get -6.

$$sort(3-\left(-6\right),4-\frac{\frac{3^{2}\left(-8\right)}{3}}{-2})$$

The opposite of -6 is 6.

$$sort(3+6,4-\frac{\frac{3^{2}\left(-8\right)}{3}}{-2})$$

Add 3 and 6 to get 9.

$$sort(9,4-\frac{\frac{3^{2}\left(-8\right)}{3}}{-2})$$

Express \frac{\frac{3^{2}\left(-8\right)}{3}}{-2} as a single fraction.

$$sort(9,4-\frac{3^{2}\left(-8\right)}{3\left(-2\right)})$$

Cancel out 2\times 3 in both numerator and denominator.

$$sort(9,4-\frac{-4\times 3}{-1})$$

Multiply -4 and 3 to get -12.

$$sort(9,4-\frac{-12}{-1})$$

Fraction \frac{-12}{-1} can be simplified to 12 by removing the negative sign from both the numerator and the denominator.

$$sort(9,4-12)$$

Subtract 12 from 4 to get -8.

$$sort(9,-8)$$

To sort the list, start from a single element 9.

$$9$$

Insert -8 to the appropriate location in the new list.

$$-8,9$$

Evaluate

$$9,-8$$