Solve (3)(-6/5)*(-2/3)+(-6/5)*(-17/3)

$$( 3 ) ( - \frac { 6 } { 5 } ) \times ( - \frac { 2 } { 3 } ) + ( - \frac { 6 } { 5 } ) \times ( - \frac { 17 } { 3 } )$$

Evaluate

$$\frac{46}{5}=9.2$$

Solution Steps

Express 3\left(-\frac{6}{5}\right) as a single fraction.

$$\frac{3\left(-6\right)}{5}\left(-\frac{2}{3}\right)-\frac{6}{5}\left(-\frac{17}{3}\right)$$

Multiply 3 and -6 to get -18.

$$\frac{-18}{5}\left(-\frac{2}{3}\right)-\frac{6}{5}\left(-\frac{17}{3}\right)$$

Fraction \frac{-18}{5} can be rewritten as -\frac{18}{5} by extracting the negative sign.

$$-\frac{18}{5}\left(-\frac{2}{3}\right)-\frac{6}{5}\left(-\frac{17}{3}\right)$$

Multiply -\frac{18}{5} times -\frac{2}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-18\left(-2\right)}{5\times 3}-\frac{6}{5}\left(-\frac{17}{3}\right)$$

Do the multiplications in the fraction \frac{-18\left(-2\right)}{5\times 3}.

$$\frac{36}{15}-\frac{6}{5}\left(-\frac{17}{3}\right)$$

Reduce the fraction \frac{36}{15} to lowest terms by extracting and canceling out 3.

$$\frac{12}{5}-\frac{6}{5}\left(-\frac{17}{3}\right)$$

Multiply -\frac{6}{5} times -\frac{17}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{12}{5}+\frac{-6\left(-17\right)}{5\times 3}$$

Do the multiplications in the fraction \frac{-6\left(-17\right)}{5\times 3}.

$$\frac{12}{5}+\frac{102}{15}$$

Reduce the fraction \frac{102}{15} to lowest terms by extracting and canceling out 3.

$$\frac{12}{5}+\frac{34}{5}$$

Since \frac{12}{5} and \frac{34}{5} have the same denominator, add them by adding their numerators.

$$\frac{12+34}{5}$$

Add 12 and 34 to get 46.

$$\frac{46}{5}$$

Factor

$$\frac{2 \cdot 23}{5} = 9\frac{1}{5} = 9.2$$