Solve (3)^2-3(3)-2-(3)^3

$$( 3 ) ^ { 2 } - 3 ( 3 ) - 2 - ( 3 ) ^ { 3 }$$

Evaluate

$$-29$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$9-3\times 3-2-3^{3}$$

Multiply 3 and 3 to get 9.

$$9-9-2-3^{3}$$

Subtract 9 from 9 to get 0.

$$0-2-3^{3}$$

Subtract 2 from 0 to get -2.

$$-2-3^{3}$$

Calculate 3 to the power of 3 and get 27.

$$-2-27$$

Subtract 27 from -2 to get -29.

$$-29$$

Factor

$$-29$$