Solve (3)^2-(2)^2*(2/3)^-3

$$( 3 ) ^ { 2 } - ( 2 ) ^ { 2 } \times ( \frac { 2 } { 3 } ) ^ { - 3 }$$

Evaluate

$$-\frac{9}{2}=-4.5$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$9-2^{2}\times \left(\frac{2}{3}\right)^{-3}$$

Calculate 2 to the power of 2 and get 4.

$$9-4\times \left(\frac{2}{3}\right)^{-3}$$

Calculate \frac{2}{3} to the power of -3 and get \frac{27}{8}.

$$9-4\times \frac{27}{8}$$

Multiply 4 and \frac{27}{8} to get \frac{27}{2}.

$$9-\frac{27}{2}$$

Subtract \frac{27}{2} from 9 to get -\frac{9}{2}.

$$-\frac{9}{2}$$

Factor

$$-\frac{9}{2} = -4\frac{1}{2} = -4.5$$