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9\left(\sqrt{5}\right)^{2}-12\sqrt{5}+6\sqrt{5}-8
Apply the distributive property by multiplying each term of 3\sqrt{5}+2 by each term of 3\sqrt{5}-4.
9\times 5-12\sqrt{5}+6\sqrt{5}-8
The square of \sqrt{5} is 5.
45-12\sqrt{5}+6\sqrt{5}-8
Multiply 9 and 5 to get 45.
45-6\sqrt{5}-8
Combine -12\sqrt{5} and 6\sqrt{5} to get -6\sqrt{5}.
37-6\sqrt{5}
Subtract 8 from 45 to get 37.