Solve (33/8-14/5)div9/10=

$$( 3 \frac { 3 } { 8 } - 1 \frac { 4 } { 5 } ) \div \frac { 9 } { 10 } =$$

Evaluate

$$\frac{7}{4}=1.75$$

Solution Steps

Multiply 3 and 8 to get 24.

$$\frac{\frac{24+3}{8}-\frac{1\times 5+4}{5}}{\frac{9}{10}}$$

Add 24 and 3 to get 27.

$$\frac{\frac{27}{8}-\frac{1\times 5+4}{5}}{\frac{9}{10}}$$

Multiply 1 and 5 to get 5.

$$\frac{\frac{27}{8}-\frac{5+4}{5}}{\frac{9}{10}}$$

Add 5 and 4 to get 9.

$$\frac{\frac{27}{8}-\frac{9}{5}}{\frac{9}{10}}$$

Least common multiple of 8 and 5 is 40. Convert \frac{27}{8} and \frac{9}{5} to fractions with denominator 40.

$$\frac{\frac{135}{40}-\frac{72}{40}}{\frac{9}{10}}$$

Since \frac{135}{40} and \frac{72}{40} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{135-72}{40}}{\frac{9}{10}}$$

Subtract 72 from 135 to get 63.

$$\frac{\frac{63}{40}}{\frac{9}{10}}$$

Divide \frac{63}{40} by \frac{9}{10} by multiplying \frac{63}{40} by the reciprocal of \frac{9}{10}.

$$\frac{63}{40}\times \frac{10}{9}$$

Multiply \frac{63}{40} times \frac{10}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{63\times 10}{40\times 9}$$

Do the multiplications in the fraction \frac{63\times 10}{40\times 9}.

$$\frac{630}{360}$$

Reduce the fraction \frac{630}{360} to lowest terms by extracting and canceling out 90.

$$\frac{7}{4}$$

Factor

$$\frac{7}{2 ^ {2}} = 1\frac{3}{4} = 1.75$$