Solve (32/3-4)*(6-3/5)

$$( 3 \frac { 2 } { 3 } - 4 ) \cdot ( 6 - \frac { 3 } { 5 } )$$

Evaluate

$$-\frac{9}{5}=-1.8$$

Solution Steps

Multiply 3 and 3 to get 9.

$$\left(\frac{9+2}{3}-4\right)\left(6-\frac{3}{5}\right)$$

Add 9 and 2 to get 11.

$$\left(\frac{11}{3}-4\right)\left(6-\frac{3}{5}\right)$$

Convert 4 to fraction \frac{12}{3}.

$$\left(\frac{11}{3}-\frac{12}{3}\right)\left(6-\frac{3}{5}\right)$$

Since \frac{11}{3} and \frac{12}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{11-12}{3}\left(6-\frac{3}{5}\right)$$

Subtract 12 from 11 to get -1.

$$-\frac{1}{3}\left(6-\frac{3}{5}\right)$$

Convert 6 to fraction \frac{30}{5}.

$$-\frac{1}{3}\left(\frac{30}{5}-\frac{3}{5}\right)$$

Since \frac{30}{5} and \frac{3}{5} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{1}{3}\times \frac{30-3}{5}$$

Subtract 3 from 30 to get 27.

$$-\frac{1}{3}\times \frac{27}{5}$$

Multiply -\frac{1}{3} times \frac{27}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-27}{3\times 5}$$

Do the multiplications in the fraction \frac{-27}{3\times 5}.

$$\frac{-27}{15}$$

Reduce the fraction \frac{-27}{15} to lowest terms by extracting and canceling out 3.

$$-\frac{9}{5}$$

Factor

$$-\frac{9}{5} = -1\frac{4}{5} = -1.8$$