Solve (3*3-4*2)^2-(2*3+2)^2=

$$( 3 \cdot 3 - 4 \cdot 2 ) ^ { 2 } - ( 2 \cdot 3 + 2 ) ^ { 2 } =$$

Evaluate

$$-63$$

Solution Steps

Multiply 3 and 3 to get 9.

$$\left(9-4\times 2\right)^{2}-\left(2\times 3+2\right)^{2}$$

Multiply 4 and 2 to get 8.

$$\left(9-8\right)^{2}-\left(2\times 3+2\right)^{2}$$

Subtract 8 from 9 to get 1.

$$1^{2}-\left(2\times 3+2\right)^{2}$$

Calculate 1 to the power of 2 and get 1.

$$1-\left(2\times 3+2\right)^{2}$$

Multiply 2 and 3 to get 6.

$$1-\left(6+2\right)^{2}$$

Add 6 and 2 to get 8.

$$1-8^{2}$$

Calculate 8 to the power of 2 and get 64.

$$1-64$$

Subtract 64 from 1 to get -63.

$$-63$$

Factor

$$-63$$