Solve (3*2^{2}-10)^3*(3^3+2^3):7-10*2^3

$$( 3 \cdot 2 ^ { 2 } - 10 ) ^ { 3 } \cdot ( 3 ^ { 3 } + 2 ^ { 3 } ) : 7 - 10 \cdot 2 ^ { 3 }$$

Evaluate

$$-40$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\frac{\left(3\times 4-10\right)^{3}\left(3^{3}+2^{3}\right)}{7}-10\times 2^{3}$$

Multiply 3 and 4 to get 12.

$$\frac{\left(12-10\right)^{3}\left(3^{3}+2^{3}\right)}{7}-10\times 2^{3}$$

Subtract 10 from 12 to get 2.

$$\frac{2^{3}\left(3^{3}+2^{3}\right)}{7}-10\times 2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{8\left(3^{3}+2^{3}\right)}{7}-10\times 2^{3}$$

Calculate 3 to the power of 3 and get 27.

$$\frac{8\left(27+2^{3}\right)}{7}-10\times 2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{8\left(27+8\right)}{7}-10\times 2^{3}$$

Add 27 and 8 to get 35.

$$\frac{8\times 35}{7}-10\times 2^{3}$$

Multiply 8 and 35 to get 280.

$$\frac{280}{7}-10\times 2^{3}$$

Divide 280 by 7 to get 40.

$$40-10\times 2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$40-10\times 8$$

Multiply 10 and 8 to get 80.

$$40-80$$

Subtract 80 from 40 to get -40.

$$-40$$

Factor

$$-40$$