Solve (3^4)^3-(3^2)^3=

$$( 3 ^ { 4 } ) ^ { 3 } - ( 3 ^ { 2 } ) ^ { 3 } =$$

Evaluate

$$530712$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 4 and 3 to get 12.

$$3^{12}-\left(3^{2}\right)^{3}$$

To raise a power to another power, multiply the exponents. Multiply 2 and 3 to get 6.

$$3^{12}-3^{6}$$

Calculate 3 to the power of 12 and get 531441.

$$531441-3^{6}$$

Calculate 3 to the power of 6 and get 729.

$$531441-729$$

Subtract 729 from 531441 to get 530712.

$$530712$$

Factor

$$2^{3}\times 3^{6}\times 7\times 13$$