Solve (3^4*3^4):21^2:21^2=

$$( 3 ^ { 4 } \times 3 ^ { 4 } ) : 21 ^ { 2 } : 21 ^ { 2 } =$$

Evaluate

$$\frac{81}{2401}\approx 0.033735943$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 4 and 4 to get 8.

$$\frac{\frac{3^{8}}{21^{2}}}{21^{2}}$$

Calculate 3 to the power of 8 and get 6561.

$$\frac{\frac{6561}{21^{2}}}{21^{2}}$$

Calculate 21 to the power of 2 and get 441.

$$\frac{\frac{6561}{441}}{21^{2}}$$

Reduce the fraction \frac{6561}{441} to lowest terms by extracting and canceling out 9.

$$\frac{\frac{729}{49}}{21^{2}}$$

Calculate 21 to the power of 2 and get 441.

$$\frac{\frac{729}{49}}{441}$$

Express \frac{\frac{729}{49}}{441} as a single fraction.

$$\frac{729}{49\times 441}$$

Multiply 49 and 441 to get 21609.

$$\frac{729}{21609}$$

Reduce the fraction \frac{729}{21609} to lowest terms by extracting and canceling out 9.

$$\frac{81}{2401}$$

Factor

$$\frac{3 ^ {4}}{7 ^ {4}} = 0.03373594335693461$$