Solve (3^3+2^3)*2+18:3^2

$$( 3 ^ { 3 } + 2 ^ { 3 } ) \cdot 2 + 18 : 3 ^ { 2 }$$

Evaluate

$$72$$

Solution Steps

Calculate 3 to the power of 3 and get 27.

$$\left(27+2^{3}\right)\times 2+\frac{18}{3^{2}}$$

Calculate 2 to the power of 3 and get 8.

$$\left(27+8\right)\times 2+\frac{18}{3^{2}}$$

Add 27 and 8 to get 35.

$$35\times 2+\frac{18}{3^{2}}$$

Multiply 35 and 2 to get 70.

$$70+\frac{18}{3^{2}}$$

Calculate 3 to the power of 2 and get 9.

$$70+\frac{18}{9}$$

Divide 18 by 9 to get 2.

$$70+2$$

Add 70 and 2 to get 72.

$$72$$

Factor

$$2^{3}\times 3^{2}$$