Solve (3^2+4^-1)*2^2

$$( 3 ^ { 2 } + 4 ^ { - 1 } ) \times 2 ^ { 2 }$$

Evaluate

$$37$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$\left(9+4^{-1}\right)\times 2^{2}$$

Calculate 4 to the power of -1 and get \frac{1}{4}.

$$\left(9+\frac{1}{4}\right)\times 2^{2}$$

Add 9 and \frac{1}{4} to get \frac{37}{4}.

$$\frac{37}{4}\times 2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{37}{4}\times 4$$

Multiply \frac{37}{4} and 4 to get 37.

$$37$$

Factor

$$37$$