Solve (3^-1+3^0)^-2*2^4

$$( 3 ^ { - 1 } + 3 ^ { 0 } ) ^ { - 2 } \cdot 2 ^ { 4 }$$

Evaluate

$$9$$

Solution Steps

Calculate 3 to the power of -1 and get \frac{1}{3}.

$$\left(\frac{1}{3}+3^{0}\right)^{-2}\times 2^{4}$$

Calculate 3 to the power of 0 and get 1.

$$\left(\frac{1}{3}+1\right)^{-2}\times 2^{4}$$

Add \frac{1}{3} and 1 to get \frac{4}{3}.

$$\left(\frac{4}{3}\right)^{-2}\times 2^{4}$$

Calculate \frac{4}{3} to the power of -2 and get \frac{9}{16}.

$$\frac{9}{16}\times 2^{4}$$

Calculate 2 to the power of 4 and get 16.

$$\frac{9}{16}\times 16$$

Multiply \frac{9}{16} and 16 to get 9.

$$9$$

Factor

$$3^{2}$$