Solve for a
a = \frac{16}{3} = 5\frac{1}{3} \approx 5.333333333
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9+6a+a^{2}=25+16+a^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(3+a\right)^{2}.
9+6a+a^{2}=41+a^{2}
Add 25 and 16 to get 41.
9+6a+a^{2}-a^{2}=41
Subtract a^{2} from both sides.
9+6a=41
Combine a^{2} and -a^{2} to get 0.
6a=41-9
Subtract 9 from both sides.
6a=32
Subtract 9 from 41 to get 32.
a=\frac{32}{6}
Divide both sides by 6.
a=\frac{16}{3}
Reduce the fraction \frac{32}{6} to lowest terms by extracting and canceling out 2.
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