Solve (3+5)^2+(1+5)^2+(1+5)^2=14

$$( 3 + 5 ) ^ { 2 } + ( 1 + 5 ) ^ { 2 } + ( 1 + 5 ) ^ { 2 } = 14$$

Verify

Solution Steps

Add 3 and 5 to get 8.

$$8^{2}+\left(1+5\right)^{2}+\left(1+5\right)^{2}=14$$

Calculate 8 to the power of 2 and get 64.

$$64+\left(1+5\right)^{2}+\left(1+5\right)^{2}=14$$

Add 1 and 5 to get 6.

$$64+6^{2}+\left(1+5\right)^{2}=14$$

Calculate 6 to the power of 2 and get 36.

$$64+36+\left(1+5\right)^{2}=14$$

Add 64 and 36 to get 100.

$$100+\left(1+5\right)^{2}=14$$

Add 1 and 5 to get 6.

$$100+6^{2}=14$$

Calculate 6 to the power of 2 and get 36.

$$100+36=14$$

Add 100 and 36 to get 136.

$$136=14$$

Compare 136 and 14.

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