Solve (3+2(4-3)-2(6-8)-5)]

$$( 3 + 2 ( 4 - 3 ) - 2 ( 6 - 8 ) - 5 ) ]$$

Evaluate

$$4$$

Solution Steps

Subtract 3 from 4 to get 1.

$$3+2\times 1-2\left(6-8\right)-5$$

Multiply 2 and 1 to get 2.

$$3+2-2\left(6-8\right)-5$$

Add 3 and 2 to get 5.

$$5-2\left(6-8\right)-5$$

Subtract 8 from 6 to get -2.

$$5-2\left(-2\right)-5$$

Multiply 2 and -2 to get -4.

$$5-\left(-4\right)-5$$

The opposite of -4 is 4.

$$5+4-5$$

Add 5 and 4 to get 9.

$$9-5$$

Subtract 5 from 9 to get 4.

$$4$$

Factor

$$2^{2}$$