Solve (3+25/4)+6=-8+(3+25/4)

$$( 3 + \frac { 25 } { 4 } ) + 6 = - 8 + ( 3 + \frac { 25 } { 4 } )$$

Verify

Solution Steps

Convert 3 to fraction \frac{12}{4}.

$$\frac{12}{4}+\frac{25}{4}+6=-8+3+\frac{25}{4}$$

Since \frac{12}{4} and \frac{25}{4} have the same denominator, add them by adding their numerators.

$$\frac{12+25}{4}+6=-8+3+\frac{25}{4}$$

Add 12 and 25 to get 37.

$$\frac{37}{4}+6=-8+3+\frac{25}{4}$$

Convert 6 to fraction \frac{24}{4}.

$$\frac{37}{4}+\frac{24}{4}=-8+3+\frac{25}{4}$$

Since \frac{37}{4} and \frac{24}{4} have the same denominator, add them by adding their numerators.

$$\frac{37+24}{4}=-8+3+\frac{25}{4}$$

Add 37 and 24 to get 61.

$$\frac{61}{4}=-8+3+\frac{25}{4}$$

Add -8 and 3 to get -5.

$$\frac{61}{4}=-5+\frac{25}{4}$$

Convert -5 to fraction -\frac{20}{4}.

$$\frac{61}{4}=-\frac{20}{4}+\frac{25}{4}$$

Since -\frac{20}{4} and \frac{25}{4} have the same denominator, add them by adding their numerators.

$$\frac{61}{4}=\frac{-20+25}{4}$$

Add -20 and 25 to get 5.

$$\frac{61}{4}=\frac{5}{4}$$

Compare \frac{61}{4} and \frac{5}{4}.

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