Solve (28-53)*4+(124%4-30%5)

$$( 28 - 53 ) \cdot 4 + ( 124 \% 4 - 30 \% 5 )$$

Evaluate

$$-\frac{4827}{50}=-96.54$$

Solution Steps

Subtract 53 from 28 to get -25.

$$-25\times 4+\frac{124}{100}\times 4-\frac{30}{100}\times 5$$

Multiply -25 and 4 to get -100.

$$-100+\frac{124}{100}\times 4-\frac{30}{100}\times 5$$

Reduce the fraction \frac{124}{100} to lowest terms by extracting and canceling out 4.

$$-100+\frac{31}{25}\times 4-\frac{30}{100}\times 5$$

Express \frac{31}{25}\times 4 as a single fraction.

$$-100+\frac{31\times 4}{25}-\frac{30}{100}\times 5$$

Multiply 31 and 4 to get 124.

$$-100+\frac{124}{25}-\frac{30}{100}\times 5$$

Reduce the fraction \frac{30}{100} to lowest terms by extracting and canceling out 10.

$$-100+\frac{124}{25}-\frac{3}{10}\times 5$$

Express \frac{3}{10}\times 5 as a single fraction.

$$-100+\frac{124}{25}-\frac{3\times 5}{10}$$

Multiply 3 and 5 to get 15.

$$-100+\frac{124}{25}-\frac{15}{10}$$

Reduce the fraction \frac{15}{10} to lowest terms by extracting and canceling out 5.

$$-100+\frac{124}{25}-\frac{3}{2}$$

Least common multiple of 25 and 2 is 50. Convert \frac{124}{25} and \frac{3}{2} to fractions with denominator 50.

$$-100+\frac{248}{50}-\frac{75}{50}$$

Since \frac{248}{50} and \frac{75}{50} have the same denominator, subtract them by subtracting their numerators.

$$-100+\frac{248-75}{50}$$

Subtract 75 from 248 to get 173.

$$-100+\frac{173}{50}$$

Convert -100 to fraction -\frac{5000}{50}.

$$-\frac{5000}{50}+\frac{173}{50}$$

Since -\frac{5000}{50} and \frac{173}{50} have the same denominator, add them by adding their numerators.

$$\frac{-5000+173}{50}$$

Add -5000 and 173 to get -4827.

$$-\frac{4827}{50}$$

Factor

$$-\frac{4827}{50} = -96\frac{27}{50} = -96.54$$