Evaluate
\frac{1}{9\left(ab\right)^{\frac{2}{3}}}
Differentiate w.r.t. a
-\frac{2}{27b^{\frac{2}{3}}a^{\frac{5}{3}}}
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27^{-\frac{2}{3}}a^{-\frac{2}{3}}b^{-\frac{2}{3}}
Expand \left(27ab\right)^{-\frac{2}{3}}.
\frac{1}{9}a^{-\frac{2}{3}}b^{-\frac{2}{3}}
Calculate 27 to the power of -\frac{2}{3} and get \frac{1}{9}.
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