Solve (25-4)+3-(2-5*2)+(5+16div4)-5+(10-2^3)

$$( 25 - 4 ) + 3 - ( 2 - 5 * 2 ) + ( 5 + 16 \div 4 ) - 5 + ( 10 - 2 ^ { 3 } )$$

Evaluate

$$38$$

Solution Steps

Subtract 4 from 25 to get 21.

$$21+3-\left(2-5\times 2\right)+5+\frac{16}{4}-5+10-2^{3}$$

Add 21 and 3 to get 24.

$$24-\left(2-5\times 2\right)+5+\frac{16}{4}-5+10-2^{3}$$

Multiply 5 and 2 to get 10.

$$24-\left(2-10\right)+5+\frac{16}{4}-5+10-2^{3}$$

Subtract 10 from 2 to get -8.

$$24-\left(-8\right)+5+\frac{16}{4}-5+10-2^{3}$$

The opposite of -8 is 8.

$$24+8+5+\frac{16}{4}-5+10-2^{3}$$

Add 24 and 8 to get 32.

$$32+5+\frac{16}{4}-5+10-2^{3}$$

Add 32 and 5 to get 37.

$$37+\frac{16}{4}-5+10-2^{3}$$

Divide 16 by 4 to get 4.

$$37+4-5+10-2^{3}$$

Add 37 and 4 to get 41.

$$41-5+10-2^{3}$$

Subtract 5 from 41 to get 36.

$$36+10-2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$36+10-8$$

Subtract 8 from 10 to get 2.

$$36+2$$

Add 36 and 2 to get 38.

$$38$$

Factor

$$2\times 19$$