Solve (25+425+1/25-2)div1/25+1=

$$( 25 + \frac { 425 + 1 } { 25 - 2 } ) \div \frac { 1 } { 25 } + 1 =$$

Evaluate

$$\frac{25048}{23}\approx 1089.043478261$$

Solution Steps

Add 425 and 1 to get 426.

$$\frac{25+\frac{426}{25-2}}{\frac{1}{25}}+1$$

Subtract 2 from 25 to get 23.

$$\frac{25+\frac{426}{23}}{\frac{1}{25}}+1$$

Convert 25 to fraction \frac{575}{23}.

$$\frac{\frac{575}{23}+\frac{426}{23}}{\frac{1}{25}}+1$$

Since \frac{575}{23} and \frac{426}{23} have the same denominator, add them by adding their numerators.

$$\frac{\frac{575+426}{23}}{\frac{1}{25}}+1$$

Add 575 and 426 to get 1001.

$$\frac{\frac{1001}{23}}{\frac{1}{25}}+1$$

Divide \frac{1001}{23} by \frac{1}{25} by multiplying \frac{1001}{23} by the reciprocal of \frac{1}{25}.

$$\frac{1001}{23}\times 25+1$$

Express \frac{1001}{23}\times 25 as a single fraction.

$$\frac{1001\times 25}{23}+1$$

Multiply 1001 and 25 to get 25025.

$$\frac{25025}{23}+1$$

Convert 1 to fraction \frac{23}{23}.

$$\frac{25025}{23}+\frac{23}{23}$$

Since \frac{25025}{23} and \frac{23}{23} have the same denominator, add them by adding their numerators.

$$\frac{25025+23}{23}$$

Add 25025 and 23 to get 25048.

$$\frac{25048}{23}$$

Factor

$$\frac{2 ^ {3} \cdot 31 \cdot 101}{23} = 1089\frac{1}{23} = 1089.0434782608695$$